Base | Representation |
---|---|
bin | 1010010010100101011011… |
… | …0111110010010010001000 |
3 | 1111001122110002012200002021 |
4 | 2210221112313302102020 |
5 | 2440333343214301440 |
6 | 40021433023014224 |
7 | 2245303261263601 |
oct | 244512667622210 |
9 | 44048402180067 |
10 | 11314401322120 |
11 | 3672457642716 |
12 | 132898213a374 |
13 | 640c35a46b30 |
14 | 2b18971bada8 |
15 | 1494a832184a |
hex | a4a56df2488 |
11314401322120 has 64 divisors (see below), whose sum is σ = 27418860126000. Its totient is φ = 4177138188288.
The previous prime is 11314401322093. The next prime is 11314401322241. The reversal of 11314401322120 is 2122310441311.
It can be written as a sum of positive squares in 8 ways, for example, as 3170443769476 + 8143957552644 = 1780574^2 + 2853762^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3212976 + ... + 5740384.
Almost surely, 211314401322120 is an apocalyptic number.
11314401322120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11314401322120 is an abundant number, since it is smaller than the sum of its proper divisors (16104458803880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11314401322120 is a wasteful number, since it uses less digits than its factorization.
11314401322120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2536042 (or 2536038 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 11314401322120 its reverse (2122310441311), we get a palindrome (13436711763431).
The spelling of 11314401322120 in words is "eleven trillion, three hundred fourteen billion, four hundred one million, three hundred twenty-two thousand, one hundred twenty".
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