113144014121130 has 24 divisors (see below), whose sum is σ = 294174436715172. Its totient is φ = 30171737098944.

The previous prime is 113144014121129. The next prime is 113144014121153. The reversal of 113144014121130 is 31121410441311.

113144014121130 is a `hidden beast` number, since 1 + 1 + 3 + 1 + 4 + 401 + 4 + 121 + 130 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 112385165808969 + 758848312161 = 10601187^2 + 871119^2 .

It is a junction number, because it is equal to n+sod(n) for n = 113144014121094 and 113144014121103.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 628577856139 + ... + 628577856318.

Almost surely, 2^{113144014121130} is an apocalyptic number.

113144014121130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113144014121130 is an abundant number, since it is smaller than the sum of its proper divisors (181030422594042).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113144014121130 is a wasteful number, since it uses less digits than its factorization.

113144014121130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1257155712470 (or 1257155712467 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 27.

Adding to 113144014121130 its reverse (31121410441311), we get a palindrome (144265424562441).

The spelling of 113144014121130 in words is "one hundred thirteen trillion, one hundred forty-four billion, fourteen million, one hundred twenty-one thousand, one hundred thirty".