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113145743 is a prime number
BaseRepresentation
bin1101011111001…
…11011110001111
321212220101210002
412233213132033
5212431130433
615121034515
72542502654
oct657473617
9255811702
10113145743
1158960087
1231a85a3b
131a597159
1411053c2b
159dee9e8
hex6be778f

113145743 has 2 divisors, whose sum is σ = 113145744. Its totient is φ = 113145742.

The previous prime is 113145737. The next prime is 113145749. The reversal of 113145743 is 347541311.

It is a balanced prime because it is at equal distance from previous prime (113145737) and next prime (113145749).

It is a cyclic number.

It is not a de Polignac number, because 113145743 - 218 = 112883599 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113145749) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56572871 + 56572872.

It is an arithmetic number, because the mean of its divisors is an integer number (56572872).

Almost surely, 2113145743 is an apocalyptic number.

113145743 is a deficient number, since it is larger than the sum of its proper divisors (1).

113145743 is an equidigital number, since it uses as much as digits as its factorization.

113145743 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5040, while the sum is 29.

The square root of 113145743 is about 10636.9987778508. The cubic root of 113145743 is about 483.6665722006. Note that the first 3 decimals are identical.

The spelling of 113145743 in words is "one hundred thirteen million, one hundred forty-five thousand, seven hundred forty-three".