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113153108141 is a prime number
BaseRepresentation
bin110100101100001110…
…0110110100010101101
3101211001211112110121002
41221120130312202231
53323214143430031
6123552023450045
711114016356363
oct1513034664255
9354054473532
10113153108141
1143a95a85a07
1219b1a8b6925
13a89382ac78
145695c83633
152e23d31ccb
hex1a587368ad

113153108141 has 2 divisors, whose sum is σ = 113153108142. Its totient is φ = 113153108140.

The previous prime is 113153108129. The next prime is 113153108161. The reversal of 113153108141 is 141801351311.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99890130916 + 13262977225 = 316054^2 + 115165^2 .

It is a cyclic number.

It is not a de Polignac number, because 113153108141 - 210 = 113153107117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113153108161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56576554070 + 56576554071.

It is an arithmetic number, because the mean of its divisors is an integer number (56576554071).

Almost surely, 2113153108141 is an apocalyptic number.

It is an amenable number.

113153108141 is a deficient number, since it is larger than the sum of its proper divisors (1).

113153108141 is an equidigital number, since it uses as much as digits as its factorization.

113153108141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 29.

Adding to 113153108141 its reverse (141801351311), we get a palindrome (254954459452).

The spelling of 113153108141 in words is "one hundred thirteen billion, one hundred fifty-three million, one hundred eight thousand, one hundred forty-one".