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11315335181 is a prime number
BaseRepresentation
bin10101000100111001…
…00101000000001101
31002012120210120210012
422202130211000031
5141133211211211
65110450523005
7550255522253
oct124234450015
932176716705
1011315335181
114887236887
122239596465
1310b4364507
14794b165d3
154635cbd8b
hex2a272500d

11315335181 has 2 divisors, whose sum is σ = 11315335182. Its totient is φ = 11315335180.

The previous prime is 11315335151. The next prime is 11315335307. The reversal of 11315335181 is 18153351311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11204222500 + 111112681 = 105850^2 + 10541^2 .

It is an emirp because it is prime and its reverse (18153351311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11315335181 - 214 = 11315318797 is a prime.

It is a super-2 number, since 2×113153351812 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11315335111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657667590 + 5657667591.

It is an arithmetic number, because the mean of its divisors is an integer number (5657667591).

Almost surely, 211315335181 is an apocalyptic number.

It is an amenable number.

11315335181 is a deficient number, since it is larger than the sum of its proper divisors (1).

11315335181 is an equidigital number, since it uses as much as digits as its factorization.

11315335181 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5400, while the sum is 32.

Adding to 11315335181 its reverse (18153351311), we get a palindrome (29468686492).

The spelling of 11315335181 in words is "eleven billion, three hundred fifteen million, three hundred thirty-five thousand, one hundred eighty-one".