Base | Representation |
---|---|
bin | 11001101110101000010001… |
… | …100000000100100001111110 |
3 | 112211122120010111021010212221 |
4 | 121232220101200010201332 |
5 | 104312414432003002004 |
6 | 1040354530414515554 |
7 | 32556133553130160 |
oct | 3156502140044176 |
9 | 484576114233787 |
10 | 113155502000254 |
11 | 33066a84a1526a |
12 | 10836364805bba |
13 | 4b1a697214a5c |
14 | 1dd2a81202930 |
15 | d1367aa9d354 |
hex | 66ea1180487e |
113155502000254 has 32 divisors (see below), whose sum is σ = 194196894958080. Its totient is φ = 48441222325152.
The previous prime is 113155502000213. The next prime is 113155502000257. The reversal of 113155502000254 is 452000205551311.
It is a super-3 number, since 3×1131555020002543 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113155502000257) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 85855057 + ... + 87163075.
It is an arithmetic number, because the mean of its divisors is an integer number (6068652967440).
Almost surely, 2113155502000254 is an apocalyptic number.
113155502000254 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
113155502000254 is a deficient number, since it is larger than the sum of its proper divisors (81041392957826).
113155502000254 is a wasteful number, since it uses less digits than its factorization.
113155502000254 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1314904.
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 113155502000254 its reverse (452000205551311), we get a palindrome (565155707551565).
The spelling of 113155502000254 in words is "one hundred thirteen trillion, one hundred fifty-five billion, five hundred two million, two hundred fifty-four", and thus it is an aban number.
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