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11315612654453 is a prime number
BaseRepresentation
bin1010010010101001111100…
…0100101001101101110101
31111001202120111112201122202
42210222133010221231311
52440343333314420303
640022153134034245
72245345300401002
oct244523704515565
944052514481582
1011315612654453
113672a19389618
12132905b948985
136410999a8423
142b197001a8a9
15149529849c88
hexa4a9f129b75

11315612654453 has 2 divisors, whose sum is σ = 11315612654454. Its totient is φ = 11315612654452.

The previous prime is 11315612654419. The next prime is 11315612654473. The reversal of 11315612654453 is 35445621651311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8170782137764 + 3144830516689 = 2858458^2 + 1773367^2 .

It is a cyclic number.

It is not a de Polignac number, because 11315612654453 - 218 = 11315612392309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11315612654398 and 11315612654407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11315612654473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657806327226 + 5657806327227.

It is an arithmetic number, because the mean of its divisors is an integer number (5657806327227).

Almost surely, 211315612654453 is an apocalyptic number.

It is an amenable number.

11315612654453 is a deficient number, since it is larger than the sum of its proper divisors (1).

11315612654453 is an equidigital number, since it uses as much as digits as its factorization.

11315612654453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296000, while the sum is 47.

The spelling of 11315612654453 in words is "eleven trillion, three hundred fifteen billion, six hundred twelve million, six hundred fifty-four thousand, four hundred fifty-three".