Base | Representation |
---|---|
bin | 1010010010111000000010… |
… | …1011110100100011010101 |
3 | 1111002010100021221211210101 |
4 | 2210232000223310203111 |
5 | 2440424111313433203 |
6 | 40024020510454101 |
7 | 2245541141514154 |
oct | 244560053644325 |
9 | 44063307854711 |
10 | 11319397796053 |
11 | 3674590a61516 |
12 | 1329937504331 |
13 | 641550c3c799 |
14 | 2b1c0ca0159b |
15 | 14969bccd41d |
hex | a4b80af48d5 |
11319397796053 has 2 divisors, whose sum is σ = 11319397796054. Its totient is φ = 11319397796052.
The previous prime is 11319397796039. The next prime is 11319397796099. The reversal of 11319397796053 is 35069779391311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6560267935204 + 4759129860849 = 2561302^2 + 2181543^2 .
It is a cyclic number.
It is not a de Polignac number, because 11319397796053 - 221 = 11319395698901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11319397796023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5659698898026 + 5659698898027.
It is an arithmetic number, because the mean of its divisors is an integer number (5659698898027).
Almost surely, 211319397796053 is an apocalyptic number.
It is an amenable number.
11319397796053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11319397796053 is an equidigital number, since it uses as much as digits as its factorization.
11319397796053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28934010, while the sum is 64.
The spelling of 11319397796053 in words is "eleven trillion, three hundred nineteen billion, three hundred ninety-seven million, seven hundred ninety-six thousand, fifty-three".
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