Base | Representation |
---|---|
bin | 10000011110010000100… |
… | …101010100101101110100 |
3 | 11000012220011122222220200 |
4 | 100132100211110231310 |
5 | 122021320014232012 |
6 | 2224011245400500 |
7 | 144533032051566 |
oct | 20362045245564 |
9 | 4005804588820 |
10 | 1132002102132 |
11 | 3a7096747a90 |
12 | 163481269130 |
13 | 82993ba2495 |
14 | 3cb09797336 |
15 | 1e6a52553dc |
hex | 10790954b74 |
1132002102132 has 72 divisors (see below), whose sum is σ = 3124914042432. Its totient is φ = 342664732800.
The previous prime is 1132002102131. The next prime is 1132002102149. The reversal of 1132002102132 is 2312012002311.
1132002102132 is a `hidden beast` number, since 1 + 1 + 320 + 0 + 210 + 2 + 132 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1132002102131) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1154344 + ... + 1896447.
Almost surely, 21132002102132 is an apocalyptic number.
1132002102132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1132002102132 is an abundant number, since it is smaller than the sum of its proper divisors (1992911940300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1132002102132 is a wasteful number, since it uses less digits than its factorization.
1132002102132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3051749 (or 3051744 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 1132002102132 its reverse (2312012002311), we get a palindrome (3444014104443).
The spelling of 1132002102132 in words is "one trillion, one hundred thirty-two billion, two million, one hundred two thousand, one hundred thirty-two".
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