Base | Representation |
---|---|
bin | 110100101101101000… |
… | …1000010110010111101 |
3 | 101211012010102022100201 |
4 | 1221123101002302331 |
5 | 3323313242004003 |
6 | 124000432123501 |
7 | 11115132023113 |
oct | 1513321026275 |
9 | 354163368321 |
10 | 113200344253 |
11 | 4400a709117 |
12 | 19b32696591 |
13 | a8a0559329 |
14 | 569c25bab3 |
15 | 2e28062b1d |
hex | 1a5b442cbd |
113200344253 has 2 divisors, whose sum is σ = 113200344254. Its totient is φ = 113200344252.
The previous prime is 113200344239. The next prime is 113200344371. The reversal of 113200344253 is 352443002311.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70600209849 + 42600134404 = 265707^2 + 206398^2 .
It is a cyclic number.
It is not a de Polignac number, because 113200344253 - 213 = 113200336061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113200344223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600172126 + 56600172127.
It is an arithmetic number, because the mean of its divisors is an integer number (56600172127).
Almost surely, 2113200344253 is an apocalyptic number.
It is an amenable number.
113200344253 is a deficient number, since it is larger than the sum of its proper divisors (1).
113200344253 is an equidigital number, since it uses as much as digits as its factorization.
113200344253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 113200344253 its reverse (352443002311), we get a palindrome (465643346564).
The spelling of 113200344253 in words is "one hundred thirteen billion, two hundred million, three hundred forty-four thousand, two hundred fifty-three".
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