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113201151253 is a prime number
BaseRepresentation
bin110100101101101010…
…0000111110100010101
3101211012011221022100121
41221123110013310111
53323313443320003
6124000501311541
711115141623641
oct1513324076425
9354164838317
10113201151253
114401010a463
1219b32a055b1
13a8a077c748
14569c3cbc21
152e28171cbd
hex1a5b507d15

113201151253 has 2 divisors, whose sum is σ = 113201151254. Its totient is φ = 113201151252.

The previous prime is 113201151241. The next prime is 113201151277. The reversal of 113201151253 is 352151102311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108199549969 + 5001601284 = 328937^2 + 70722^2 .

It is a cyclic number.

It is not a de Polignac number, because 113201151253 - 225 = 113167596821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113201158253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600575626 + 56600575627.

It is an arithmetic number, because the mean of its divisors is an integer number (56600575627).

Almost surely, 2113201151253 is an apocalyptic number.

It is an amenable number.

113201151253 is a deficient number, since it is larger than the sum of its proper divisors (1).

113201151253 is an equidigital number, since it uses as much as digits as its factorization.

113201151253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 113201151253 its reverse (352151102311), we get a palindrome (465352253564).

The spelling of 113201151253 in words is "one hundred thirteen billion, two hundred one million, one hundred fifty-one thousand, two hundred fifty-three".