Base | Representation |
---|---|
bin | 11001101111010010110110… |
… | …100100101001010111010101 |
3 | 112211210221010201211201121011 |
4 | 121233102312210221113111 |
5 | 104314142100101111201 |
6 | 1040431531214052221 |
7 | 32562342534153016 |
oct | 3157226644512725 |
9 | 484727121751534 |
10 | 113201221113301 |
11 | 33084406194612 |
12 | 108431a3aaa071 |
13 | 4b21aa20c7a79 |
14 | 1dd4d7b18300d |
15 | d149546d7151 |
hex | 66f4b69295d5 |
113201221113301 has 2 divisors, whose sum is σ = 113201221113302. Its totient is φ = 113201221113300.
The previous prime is 113201221113271. The next prime is 113201221113307. The reversal of 113201221113301 is 103311122102311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 57271748196100 + 55929472917201 = 7567810^2 + 7478601^2 .
It is a cyclic number.
It is not a de Polignac number, because 113201221113301 - 25 = 113201221113269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113201221113307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56600610556650 + 56600610556651.
It is an arithmetic number, because the mean of its divisors is an integer number (56600610556651).
Almost surely, 2113201221113301 is an apocalyptic number.
It is an amenable number.
113201221113301 is a deficient number, since it is larger than the sum of its proper divisors (1).
113201221113301 is an equidigital number, since it uses as much as digits as its factorization.
113201221113301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 113201221113301 its reverse (103311122102311), we get a palindrome (216512343215612).
The spelling of 113201221113301 in words is "one hundred thirteen trillion, two hundred one billion, two hundred twenty-one million, one hundred thirteen thousand, three hundred one".
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