Base | Representation |
---|---|
bin | 11001101111010010110110… |
… | …100100101001010111010100 |
3 | 112211210221010201211201121010 |
4 | 121233102312210221113110 |
5 | 104314142100101111200 |
6 | 1040431531214052220 |
7 | 32562342534153015 |
oct | 3157226644512724 |
9 | 484727121751533 |
10 | 113201221113300 |
11 | 33084406194611 |
12 | 108431a3aaa070 |
13 | 4b21aa20c7a78 |
14 | 1dd4d7b18300c |
15 | d149546d7150 |
hex | 66f4b69295d4 |
113201221113300 has 144 divisors (see below), whose sum is σ = 329592254745600. Its totient is φ = 29996878988160.
The previous prime is 113201221113271. The next prime is 113201221113301. The reversal of 113201221113300 is 3311122102311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113201221113301) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 303140101 + ... + 303513299.
It is an arithmetic number, because the mean of its divisors is an integer number (2288835102400).
Almost surely, 2113201221113300 is an apocalyptic number.
113201221113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113201221113300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164796127372800).
113201221113300 is an abundant number, since it is smaller than the sum of its proper divisors (216391033632300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113201221113300 is a wasteful number, since it uses less digits than its factorization.
113201221113300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 379582 (or 379575 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 113201221113300 its reverse (3311122102311), we get a palindrome (116512343215611).
The spelling of 113201221113300 in words is "one hundred thirteen trillion, two hundred one billion, two hundred twenty-one million, one hundred thirteen thousand, three hundred".
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