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11320243133 is a prime number
BaseRepresentation
bin10101000101011110…
…10011001110111101
31002012221000221020012
422202233103032331
5141140440240013
65111144033005
7550345323203
oct124257231675
932187027205
1011320243133
114889a89241
12223b162765
1310b5392424
14795633073
15463c4b1a8
hex2a2bd33bd

11320243133 has 2 divisors, whose sum is σ = 11320243134. Its totient is φ = 11320243132.

The previous prime is 11320243117. The next prime is 11320243141. The reversal of 11320243133 is 33134202311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8285004484 + 3035238649 = 91022^2 + 55093^2 .

It is a cyclic number.

It is not a de Polignac number, because 11320243133 - 24 = 11320243117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11320243099 and 11320243108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11320243153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660121566 + 5660121567.

It is an arithmetic number, because the mean of its divisors is an integer number (5660121567).

Almost surely, 211320243133 is an apocalyptic number.

It is an amenable number.

11320243133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11320243133 is an equidigital number, since it uses as much as digits as its factorization.

11320243133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 11320243133 its reverse (33134202311), we get a palindrome (44454445444).

The spelling of 11320243133 in words is "eleven billion, three hundred twenty million, two hundred forty-three thousand, one hundred thirty-three".