Base | Representation |
---|---|
bin | 10101000101011110… |
… | …10011001110111101 |
3 | 1002012221000221020012 |
4 | 22202233103032331 |
5 | 141140440240013 |
6 | 5111144033005 |
7 | 550345323203 |
oct | 124257231675 |
9 | 32187027205 |
10 | 11320243133 |
11 | 4889a89241 |
12 | 223b162765 |
13 | 10b5392424 |
14 | 795633073 |
15 | 463c4b1a8 |
hex | 2a2bd33bd |
11320243133 has 2 divisors, whose sum is σ = 11320243134. Its totient is φ = 11320243132.
The previous prime is 11320243117. The next prime is 11320243141. The reversal of 11320243133 is 33134202311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8285004484 + 3035238649 = 91022^2 + 55093^2 .
It is a cyclic number.
It is not a de Polignac number, because 11320243133 - 24 = 11320243117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11320243099 and 11320243108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11320243153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660121566 + 5660121567.
It is an arithmetic number, because the mean of its divisors is an integer number (5660121567).
Almost surely, 211320243133 is an apocalyptic number.
It is an amenable number.
11320243133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11320243133 is an equidigital number, since it uses as much as digits as its factorization.
11320243133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 11320243133 its reverse (33134202311), we get a palindrome (44454445444).
The spelling of 11320243133 in words is "eleven billion, three hundred twenty million, two hundred forty-three thousand, one hundred thirty-three".
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