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11320243153 is a prime number
BaseRepresentation
bin10101000101011110…
…10011001111010001
31002012221000221020221
422202233103033101
5141140440240103
65111144033041
7550345323232
oct124257231721
932187027227
1011320243153
114889a8925a
12223b162781
1310b539243b
14795633089
15463c4b1bd
hex2a2bd33d1

11320243153 has 2 divisors, whose sum is σ = 11320243154. Its totient is φ = 11320243152.

The previous prime is 11320243141. The next prime is 11320243163. The reversal of 11320243153 is 35134202311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10455471504 + 864771649 = 102252^2 + 29407^2 .

It is a cyclic number.

It is not a de Polignac number, because 11320243153 - 221 = 11318146001 is a prime.

It is a super-3 number, since 3×113202431533 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11320243133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660121576 + 5660121577.

It is an arithmetic number, because the mean of its divisors is an integer number (5660121577).

Almost surely, 211320243153 is an apocalyptic number.

It is an amenable number.

11320243153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11320243153 is an equidigital number, since it uses as much as digits as its factorization.

11320243153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 11320243153 its reverse (35134202311), we get a palindrome (46454445464).

The spelling of 11320243153 in words is "eleven billion, three hundred twenty million, two hundred forty-three thousand, one hundred fifty-three".