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1132101301300 = 225211321013013
BaseRepresentation
bin10000011110010110011…
…111101111010000110100
311000020011002022211120221
4100132112133233100310
5122022020413120200
62224025151504124
7144535345200154
oct20362637572064
94006132284527
101132101301300
113a7137741872
121634aa528044
13829ab5c5608
143cb18a1a764
151e6adcec91a
hex107967ef434

1132101301300 has 18 divisors (see below), whose sum is σ = 2456659824038. Its totient is φ = 452840520480.

The previous prime is 1132101301271. The next prime is 1132101301319. The reversal of 1132101301300 is 31031012311.

It can be written as a sum of positive squares in 3 ways, for example, as 394914210084 + 737187091216 = 628422^2 + 858596^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5660506407 + ... + 5660506606.

Almost surely, 21132101301300 is an apocalyptic number.

1132101301300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1132101301300 is an abundant number, since it is smaller than the sum of its proper divisors (1324558522738).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1132101301300 is a wasteful number, since it uses less digits than its factorization.

1132101301300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11321013027 (or 11321013020 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1132101301300 its reverse (31031012311), we get a palindrome (1163132313611).

The spelling of 1132101301300 in words is "one trillion, one hundred thirty-two billion, one hundred one million, three hundred one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 11321013013 22642026026 45284052052 56605065065 113210130130 226420260260 283025325325 566050650650 1132101301300