Base | Representation |
---|---|
bin | 1010010010111110110011… |
… | …1001001010010000010111 |
3 | 1111002022000211000112221101 |
4 | 2210233230321022100113 |
5 | 2440441321041412101 |
6 | 40024521001530531 |
7 | 2245634134461604 |
oct | 244575471122027 |
9 | 44068024015841 |
10 | 11321213232151 |
11 | 36753327a9529 |
12 | 132a1634a3a47 |
13 | 6417800a5824 |
14 | 2b1d41b756ab |
15 | 149756385401 |
hex | a4bece4a417 |
11321213232151 has 2 divisors, whose sum is σ = 11321213232152. Its totient is φ = 11321213232150.
The previous prime is 11321213232143. The next prime is 11321213232253. The reversal of 11321213232151 is 15123231212311.
11321213232151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11321213232151 - 23 = 11321213232143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11321213238151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660606616075 + 5660606616076.
It is an arithmetic number, because the mean of its divisors is an integer number (5660606616076).
Almost surely, 211321213232151 is an apocalyptic number.
11321213232151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11321213232151 is an equidigital number, since it uses as much as digits as its factorization.
11321213232151 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2160, while the sum is 28.
Adding to 11321213232151 its reverse (15123231212311), we get a palindrome (26444444444462).
The spelling of 11321213232151 in words is "eleven trillion, three hundred twenty-one billion, two hundred thirteen million, two hundred thirty-two thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •