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11321213232253 is a prime number
BaseRepresentation
bin1010010010111110110011…
…1001001010010001111101
31111002022000211000120002011
42210233230321022101331
52440441321041413003
640024521001531221
72245634134462111
oct244575471122175
944068024016064
1011321213232253
1136753327a9611
12132a1634a3b11
136417800a58a2
142b1d41b75741
1514975638546d
hexa4bece4a47d

11321213232253 has 2 divisors, whose sum is σ = 11321213232254. Its totient is φ = 11321213232252.

The previous prime is 11321213232151. The next prime is 11321213232271. The reversal of 11321213232253 is 35223231212311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7762810137124 + 3558403095129 = 2786182^2 + 1886373^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11321213232253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11321213232293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5660606616126 + 5660606616127.

It is an arithmetic number, because the mean of its divisors is an integer number (5660606616127).

Almost surely, 211321213232253 is an apocalyptic number.

It is an amenable number.

11321213232253 is a deficient number, since it is larger than the sum of its proper divisors (1).

11321213232253 is an equidigital number, since it uses as much as digits as its factorization.

11321213232253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12960, while the sum is 31.

Adding to 11321213232253 its reverse (35223231212311), we get a palindrome (46544444444564).

The spelling of 11321213232253 in words is "eleven trillion, three hundred twenty-one billion, two hundred thirteen million, two hundred thirty-two thousand, two hundred fifty-three".