Base | Representation |
---|---|
bin | 110100101110000001… |
… | …0011101110111001101 |
3 | 101211020000210112112121 |
4 | 1221130002131313031 |
5 | 3323330101101143 |
6 | 124002013532541 |
7 | 11115350113351 |
oct | 1513402356715 |
9 | 354200715477 |
10 | 113213300173 |
11 | 44016a58096 |
12 | 19b36aa4151 |
13 | a8a314445c |
14 | 569dc71461 |
15 | 2e292717ed |
hex | 1a5c09ddcd |
113213300173 has 2 divisors, whose sum is σ = 113213300174. Its totient is φ = 113213300172.
The previous prime is 113213300107. The next prime is 113213300197. The reversal of 113213300173 is 371003312311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 111811321924 + 1401978249 = 334382^2 + 37443^2 .
It is an emirp because it is prime and its reverse (371003312311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113213300173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113213300273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56606650086 + 56606650087.
It is an arithmetic number, because the mean of its divisors is an integer number (56606650087).
Almost surely, 2113213300173 is an apocalyptic number.
It is an amenable number.
113213300173 is a deficient number, since it is larger than the sum of its proper divisors (1).
113213300173 is an equidigital number, since it uses as much as digits as its factorization.
113213300173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 113213300173 its reverse (371003312311), we get a palindrome (484216612484).
The spelling of 113213300173 in words is "one hundred thirteen billion, two hundred thirteen million, three hundred thousand, one hundred seventy-three".
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