Base | Representation |
---|---|
bin | 110100101110000010… |
… | …1001000110100010111 |
3 | 101211020002010010002012 |
4 | 1221130011020310113 |
5 | 3323330241003112 |
6 | 124002040534435 |
7 | 11115356061014 |
oct | 1513405106427 |
9 | 354202103065 |
10 | 113214000407 |
11 | 440173961a2 |
12 | 19b3718141b |
13 | a8a332b0b1 |
14 | 569ddb470b |
15 | 2e2935e022 |
hex | 1a5c148d17 |
113214000407 has 2 divisors, whose sum is σ = 113214000408. Its totient is φ = 113214000406.
The previous prime is 113214000271. The next prime is 113214000491. The reversal of 113214000407 is 704000412311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113214000407 - 234 = 96034131223 is a prime.
It is a super-3 number, since 3×1132140004073 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113214000007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56607000203 + 56607000204.
It is an arithmetic number, because the mean of its divisors is an integer number (56607000204).
Almost surely, 2113214000407 is an apocalyptic number.
113214000407 is a deficient number, since it is larger than the sum of its proper divisors (1).
113214000407 is an equidigital number, since it uses as much as digits as its factorization.
113214000407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 113214000407 its reverse (704000412311), we get a palindrome (817214412718).
The spelling of 113214000407 in words is "one hundred thirteen billion, two hundred fourteen million, four hundred seven", and thus it is an aban number.
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