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113221253140081 is a prime number
BaseRepresentation
bin11001101111100101100000…
…100100110000111001110001
3112211212211211210122010022221
4121233211200210300321301
5104320004111300440311
61040445043050001041
732563652125446322
oct3157454044607161
9484784753563287
10113221253140081
11330919557a8849
1210847054716181
134b23945307058
141dd5d1b804449
15d1522817c671
hex66f960930e71

113221253140081 has 2 divisors, whose sum is σ = 113221253140082. Its totient is φ = 113221253140080.

The previous prime is 113221253140007. The next prime is 113221253140139. The reversal of 113221253140081 is 180041352122311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98047306749456 + 15173946390625 = 9901884^2 + 3895375^2 .

It is a cyclic number.

It is not a de Polignac number, because 113221253140081 - 229 = 113220716269169 is a prime.

It is a super-2 number, since 2×1132212531400812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (113221253140381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56610626570040 + 56610626570041.

It is an arithmetic number, because the mean of its divisors is an integer number (56610626570041).

Almost surely, 2113221253140081 is an apocalyptic number.

It is an amenable number.

113221253140081 is a deficient number, since it is larger than the sum of its proper divisors (1).

113221253140081 is an equidigital number, since it uses as much as digits as its factorization.

113221253140081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 34.

The spelling of 113221253140081 in words is "one hundred thirteen trillion, two hundred twenty-one billion, two hundred fifty-three million, one hundred forty thousand, eighty-one".