Base | Representation |
---|---|
bin | 11001101111100101100000… |
… | …100100110000111000100111 |
3 | 112211212211211210122010020012 |
4 | 121233211200210300320213 |
5 | 104320004111300440012 |
6 | 1040445043050000435 |
7 | 32563652125446155 |
oct | 3157454044607047 |
9 | 484784753563205 |
10 | 113221253140007 |
11 | 330919557a8791 |
12 | 1084705471611b |
13 | 4b23945306ccc |
14 | 1dd5d1b8043d5 |
15 | d1522817c622 |
hex | 66f960930e27 |
113221253140007 has 2 divisors, whose sum is σ = 113221253140008. Its totient is φ = 113221253140006.
The previous prime is 113221253139919. The next prime is 113221253140081. The reversal of 113221253140007 is 700041352122311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113221253140007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113221253143007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56610626570003 + 56610626570004.
It is an arithmetic number, because the mean of its divisors is an integer number (56610626570004).
Almost surely, 2113221253140007 is an apocalyptic number.
113221253140007 is a deficient number, since it is larger than the sum of its proper divisors (1).
113221253140007 is an equidigital number, since it uses as much as digits as its factorization.
113221253140007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080, while the sum is 32.
The spelling of 113221253140007 in words is "one hundred thirteen trillion, two hundred twenty-one billion, two hundred fifty-three million, one hundred forty thousand, seven".
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