Base | Representation |
---|---|
bin | 110100101110010000… |
… | …1000110100101100100 |
3 | 101211020120220120011202 |
4 | 1221130201012211210 |
5 | 3323334130100200 |
6 | 124002502022032 |
7 | 11115505302620 |
oct | 1513441064544 |
9 | 354216816152 |
10 | 113221331300 |
11 | 44020542a90 |
12 | 19b39717918 |
13 | a8a49c6abc |
14 | 56a0d62180 |
15 | 2e29d0b1d5 |
hex | 1a5c846964 |
113221331300 has 144 divisors (see below), whose sum is σ = 306658372608. Its totient is φ = 35250230400.
The previous prime is 113221331207. The next prime is 113221331329. The reversal of 113221331300 is 3133122311.
113221331300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1132213313002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7284137 + ... + 7299663.
It is an arithmetic number, because the mean of its divisors is an integer number (2129572032).
Almost surely, 2113221331300 is an apocalyptic number.
113221331300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113221331300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (153329186304).
113221331300 is an abundant number, since it is smaller than the sum of its proper divisors (193437041308).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113221331300 is a wasteful number, since it uses less digits than its factorization.
113221331300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16506 (or 16499 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 113221331300 its reverse (3133122311), we get a palindrome (116354453611).
The spelling of 113221331300 in words is "one hundred thirteen billion, two hundred twenty-one million, three hundred thirty-one thousand, three hundred".
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