Base | Representation |
---|---|
bin | 11001101111101000010110… |
… | …110110000100111101101111 |
3 | 112211220010201220210012122110 |
4 | 121233220112312010331233 |
5 | 104320031342122211030 |
6 | 1040450310325215103 |
7 | 32564120660113566 |
oct | 3157502666047557 |
9 | 484803656705573 |
10 | 113224311132015 |
11 | 33093184978406 |
12 | 10847768861493 |
13 | 4b24011a14535 |
14 | 1dd612b9c4bdd |
15 | d153568791b0 |
hex | 66fa16d84f6f |
113224311132015 has 16 divisors (see below), whose sum is σ = 182541790164096. Its totient is φ = 59925335152800.
The previous prime is 113224311132007. The next prime is 113224311132047. The reversal of 113224311132015 is 510231113422311.
It is a happy number.
It is not a de Polignac number, because 113224311132015 - 23 = 113224311132007 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28810255321 + ... + 28810259250.
It is an arithmetic number, because the mean of its divisors is an integer number (11408861885256).
Almost surely, 2113224311132015 is an apocalyptic number.
113224311132015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113224311132015 is a deficient number, since it is larger than the sum of its proper divisors (69317479032081).
113224311132015 is a wasteful number, since it uses less digits than its factorization.
113224311132015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57620514710.
The product of its (nonzero) digits is 4320, while the sum is 30.
Adding to 113224311132015 its reverse (510231113422311), we get a palindrome (623455424554326).
The spelling of 113224311132015 in words is "one hundred thirteen trillion, two hundred twenty-four billion, three hundred eleven million, one hundred thirty-two thousand, fifteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •