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11323020021149 is a prime number
BaseRepresentation
bin1010010011000101100010…
…0101100000110110011101
31111002110200201210221111102
42210301120211200312131
52441004021111134044
640025420143402445
72246026664103164
oct244613045406635
944073621727442
1011323020021149
11367607a67a881
12132a5885b3425
136419aa501a45
142b2073ad83db
1514980ecd024e
hexa4c58960d9d

11323020021149 has 2 divisors, whose sum is σ = 11323020021150. Its totient is φ = 11323020021148.

The previous prime is 11323020021101. The next prime is 11323020021197. The reversal of 11323020021149 is 94112002032311.

It is a balanced prime because it is at equal distance from previous prime (11323020021101) and next prime (11323020021197).

It can be written as a sum of positive squares in only one way, i.e., 6097763503225 + 5225256517924 = 2469365^2 + 2285882^2 .

It is a cyclic number.

It is not a de Polignac number, because 11323020021149 - 228 = 11322751585693 is a prime.

It is a super-2 number, since 2×113230200211492 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11323020021449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661510010574 + 5661510010575.

It is an arithmetic number, because the mean of its divisors is an integer number (5661510010575).

Almost surely, 211323020021149 is an apocalyptic number.

It is an amenable number.

11323020021149 is a deficient number, since it is larger than the sum of its proper divisors (1).

11323020021149 is an equidigital number, since it uses as much as digits as its factorization.

11323020021149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 11323020021149 in words is "eleven trillion, three hundred twenty-three billion, twenty million, twenty-one thousand, one hundred forty-nine".