Base | Representation |
---|---|
bin | 11001101111110000011110… |
… | …100011000100010111000001 |
3 | 112211220222020120102220002120 |
4 | 121233300132203010113001 |
5 | 104320202221224113441 |
6 | 1040454311435234453 |
7 | 32564550022613643 |
oct | 3157603643042701 |
9 | 484828216386076 |
10 | 113233030301121 |
11 | 33096949698195 |
12 | 108493a08a8a29 |
13 | 4b24aa1248bb3 |
14 | 1dd67179b6893 |
15 | d156b7081966 |
hex | 66fc1e8c45c1 |
113233030301121 has 4 divisors (see below), whose sum is σ = 150977373734832. Its totient is φ = 75488686867412.
The previous prime is 113233030301113. The next prime is 113233030301129. The reversal of 113233030301121 is 121103030332311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (113233030301113) and next prime (113233030301129).
It is a cyclic number.
It is not a de Polignac number, because 113233030301121 - 23 = 113233030301113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113233030301091 and 113233030301100.
It is not an unprimeable number, because it can be changed into a prime (113233030301129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18872171716851 + ... + 18872171716856.
It is an arithmetic number, because the mean of its divisors is an integer number (37744343433708).
Almost surely, 2113233030301121 is an apocalyptic number.
It is an amenable number.
113233030301121 is a deficient number, since it is larger than the sum of its proper divisors (37744343433711).
113233030301121 is an equidigital number, since it uses as much as digits as its factorization.
113233030301121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37744343433710.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 113233030301121 its reverse (121103030332311), we get a palindrome (234336060633432).
The spelling of 113233030301121 in words is "one hundred thirteen trillion, two hundred thirty-three billion, thirty million, three hundred one thousand, one hundred twenty-one".
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