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113233030301121 = 337744343433707
BaseRepresentation
bin11001101111110000011110…
…100011000100010111000001
3112211220222020120102220002120
4121233300132203010113001
5104320202221224113441
61040454311435234453
732564550022613643
oct3157603643042701
9484828216386076
10113233030301121
1133096949698195
12108493a08a8a29
134b24aa1248bb3
141dd67179b6893
15d156b7081966
hex66fc1e8c45c1

113233030301121 has 4 divisors (see below), whose sum is σ = 150977373734832. Its totient is φ = 75488686867412.

The previous prime is 113233030301113. The next prime is 113233030301129. The reversal of 113233030301121 is 121103030332311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (113233030301113) and next prime (113233030301129).

It is a cyclic number.

It is not a de Polignac number, because 113233030301121 - 23 = 113233030301113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113233030301091 and 113233030301100.

It is not an unprimeable number, because it can be changed into a prime (113233030301129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18872171716851 + ... + 18872171716856.

It is an arithmetic number, because the mean of its divisors is an integer number (37744343433708).

Almost surely, 2113233030301121 is an apocalyptic number.

It is an amenable number.

113233030301121 is a deficient number, since it is larger than the sum of its proper divisors (37744343433711).

113233030301121 is an equidigital number, since it uses as much as digits as its factorization.

113233030301121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37744343433710.

The product of its (nonzero) digits is 972, while the sum is 24.

Adding to 113233030301121 its reverse (121103030332311), we get a palindrome (234336060633432).

The spelling of 113233030301121 in words is "one hundred thirteen trillion, two hundred thirty-three billion, thirty million, three hundred one thousand, one hundred twenty-one".

Divisors: 1 3 37744343433707 113233030301121