Base | Representation |
---|---|
bin | 11001101111110000011110… |
… | …100011000100010111000010 |
3 | 112211220222020120102220002121 |
4 | 121233300132203010113002 |
5 | 104320202221224113442 |
6 | 1040454311435234454 |
7 | 32564550022613644 |
oct | 3157603643042702 |
9 | 484828216386077 |
10 | 113233030301122 |
11 | 33096949698196 |
12 | 108493a08a8a2a |
13 | 4b24aa1248bb4 |
14 | 1dd67179b6894 |
15 | d156b7081967 |
hex | 66fc1e8c45c2 |
113233030301122 has 4 divisors (see below), whose sum is σ = 169849545451686. Its totient is φ = 56616515150560.
The previous prime is 113233030301113. The next prime is 113233030301129. The reversal of 113233030301122 is 221103030332311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 95122549980241 + 18110480320881 = 9753079^2 + 4255641^2 .
It is not an unprimeable number, because it can be changed into a prime (113233030301129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28308257575279 + ... + 28308257575282.
Almost surely, 2113233030301122 is an apocalyptic number.
113233030301122 is a deficient number, since it is larger than the sum of its proper divisors (56616515150564).
113233030301122 is an equidigital number, since it uses as much as digits as its factorization.
113233030301122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56616515150563.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 113233030301122 its reverse (221103030332311), we get a palindrome (334336060633433).
The spelling of 113233030301122 in words is "one hundred thirteen trillion, two hundred thirty-three billion, thirty million, three hundred one thousand, one hundred twenty-two".
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