Base | Representation |
---|---|
bin | 1010010011000110101010… |
… | …1001110010110100010111 |
3 | 1111002111110212011122001221 |
4 | 2210301222221302310113 |
5 | 2441010131210230312 |
6 | 40025510212231211 |
7 | 2246040334363621 |
oct | 244615251626427 |
9 | 44074425148057 |
10 | 11323323133207 |
11 | 367621578a408 |
12 | 132a65200b507 |
13 | 641a2824c1a7 |
14 | 2b20a207bc11 |
15 | 14982b706207 |
hex | a4c6aa72d17 |
11323323133207 has 2 divisors, whose sum is σ = 11323323133208. Its totient is φ = 11323323133206.
The previous prime is 11323323133193. The next prime is 11323323133247. The reversal of 11323323133207 is 70233132332311.
11323323133207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11323323133207 is a prime.
It is a super-2 number, since 2×113233231332072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11323323133247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661661566603 + 5661661566604.
It is an arithmetic number, because the mean of its divisors is an integer number (5661661566604).
Almost surely, 211323323133207 is an apocalyptic number.
11323323133207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323323133207 is an equidigital number, since it uses as much as digits as its factorization.
11323323133207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 34.
Adding to 11323323133207 its reverse (70233132332311), we get a palindrome (81556455465518).
The spelling of 11323323133207 in words is "eleven trillion, three hundred twenty-three billion, three hundred twenty-three million, one hundred thirty-three thousand, two hundred seven".
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