Base | Representation |
---|---|
bin | 1010010011000110101100… |
… | …1000100101000000110111 |
3 | 1111002111111102100121220212 |
4 | 2210301223020211000313 |
5 | 2441010140242000002 |
6 | 40025511101220035 |
7 | 2246040463104236 |
oct | 244615310450067 |
9 | 44074442317825 |
10 | 11323331203127 |
11 | 367621a2a1469 |
12 | 132a65486161b |
13 | 641a29b163a8 |
14 | 2b20a317cb1d |
15 | 14982c29c352 |
hex | a4c6b225037 |
11323331203127 has 2 divisors, whose sum is σ = 11323331203128. Its totient is φ = 11323331203126.
The previous prime is 11323331203117. The next prime is 11323331203193. The reversal of 11323331203127 is 72130213332311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11323331203127 - 224 = 11323314425911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11323331203093 and 11323331203102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11323331203117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661665601563 + 5661665601564.
It is an arithmetic number, because the mean of its divisors is an integer number (5661665601564).
Almost surely, 211323331203127 is an apocalyptic number.
11323331203127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323331203127 is an equidigital number, since it uses as much as digits as its factorization.
11323331203127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13608, while the sum is 32.
Adding to 11323331203127 its reverse (72130213332311), we get a palindrome (83453544535438).
The spelling of 11323331203127 in words is "eleven trillion, three hundred twenty-three billion, three hundred thirty-one million, two hundred three thousand, one hundred twenty-seven".
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