Base | Representation |
---|---|
bin | 11001101111110001011000… |
… | …100011001111000101101111 |
3 | 112211221001202101112122011211 |
4 | 121233301120203033011233 |
5 | 104320211214334023344 |
6 | 1040454552200455251 |
7 | 32564613110202502 |
oct | 3157613043170557 |
9 | 484831671478154 |
10 | 113234003423599 |
11 | 330972a8a23543 |
12 | 1084961277a527 |
13 | 4b24bc7a35406 |
14 | 1dd67aad29139 |
15 | d15722704334 |
hex | 66fc588cf16f |
113234003423599 has 2 divisors, whose sum is σ = 113234003423600. Its totient is φ = 113234003423598.
The previous prime is 113234003423539. The next prime is 113234003423627. The reversal of 113234003423599 is 995324300432311.
It is a strong prime.
It is an emirp because it is prime and its reverse (995324300432311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113234003423599 - 29 = 113234003423087 is a prime.
It is a super-2 number, since 2×1132340034235992 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113234003423539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56617001711799 + 56617001711800.
It is an arithmetic number, because the mean of its divisors is an integer number (56617001711800).
Almost surely, 2113234003423599 is an apocalyptic number.
113234003423599 is a deficient number, since it is larger than the sum of its proper divisors (1).
113234003423599 is an equidigital number, since it uses as much as digits as its factorization.
113234003423599 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2099520, while the sum is 49.
The spelling of 113234003423599 in words is "one hundred thirteen trillion, two hundred thirty-four billion, three million, four hundred twenty-three thousand, five hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •