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113234003423539 is a prime number
BaseRepresentation
bin11001101111110001011000…
…100011001111000100110011
3112211221001202101112122002121
4121233301120203033010303
5104320211214334023124
61040454552200455111
732564613110202355
oct3157613043170463
9484831671478077
10113234003423539
11330972a8a23499
121084961277a497
134b24bc7a3538b
141dd67aad290d5
15d157227042e4
hex66fc588cf133

113234003423539 has 2 divisors, whose sum is σ = 113234003423540. Its totient is φ = 113234003423538.

The previous prime is 113234003423537. The next prime is 113234003423599. The reversal of 113234003423539 is 935324300432311.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (935324300432311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113234003423539 - 21 = 113234003423537 is a prime.

Together with 113234003423537, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 113234003423495 and 113234003423504.

It is not a weakly prime, because it can be changed into another prime (113234003423537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56617001711769 + 56617001711770.

It is an arithmetic number, because the mean of its divisors is an integer number (56617001711770).

Almost surely, 2113234003423539 is an apocalyptic number.

113234003423539 is a deficient number, since it is larger than the sum of its proper divisors (1).

113234003423539 is an equidigital number, since it uses as much as digits as its factorization.

113234003423539 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 699840, while the sum is 43.

The spelling of 113234003423539 in words is "one hundred thirteen trillion, two hundred thirty-four billion, three million, four hundred twenty-three thousand, five hundred thirty-nine".