Base | Representation |
---|---|
bin | 10101000101111100… |
… | …00110000100111111 |
3 | 1002020012022222012222 |
4 | 22202332012010333 |
5 | 141142433341112 |
6 | 5111403115555 |
7 | 550423305134 |
oct | 124276060477 |
9 | 32205288188 |
10 | 11324121407 |
11 | 4891198025 |
12 | 2240512bbb |
13 | 10b611c771 |
14 | 795d6258b |
15 | 464265372 |
hex | 2a2f8613f |
11324121407 has 2 divisors, whose sum is σ = 11324121408. Its totient is φ = 11324121406.
The previous prime is 11324121373. The next prime is 11324121421. The reversal of 11324121407 is 70412142311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11324121407 - 210 = 11324120383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11324121437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662060703 + 5662060704.
It is an arithmetic number, because the mean of its divisors is an integer number (5662060704).
Almost surely, 211324121407 is an apocalyptic number.
11324121407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11324121407 is an equidigital number, since it uses as much as digits as its factorization.
11324121407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 11324121407 its reverse (70412142311), we get a palindrome (81736263718).
The spelling of 11324121407 in words is "eleven billion, three hundred twenty-four million, one hundred twenty-one thousand, four hundred seven".
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