Base | Representation |
---|---|
bin | 10101000101111100… |
… | …00110000101001101 |
3 | 1002020012022222020111 |
4 | 22202332012011031 |
5 | 141142433341141 |
6 | 5111403120021 |
7 | 550423305154 |
oct | 124276060515 |
9 | 32205288214 |
10 | 11324121421 |
11 | 4891198038 |
12 | 2240513011 |
13 | 10b611c782 |
14 | 795d6259b |
15 | 464265381 |
hex | 2a2f8614d |
11324121421 has 2 divisors, whose sum is σ = 11324121422. Its totient is φ = 11324121420.
The previous prime is 11324121407. The next prime is 11324121433. The reversal of 11324121421 is 12412142311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9218688196 + 2105433225 = 96014^2 + 45885^2 .
It is a cyclic number.
It is not a de Polignac number, because 11324121421 - 221 = 11322024269 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11324121392 and 11324121401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11324521421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662060710 + 5662060711.
It is an arithmetic number, because the mean of its divisors is an integer number (5662060711).
Almost surely, 211324121421 is an apocalyptic number.
It is an amenable number.
11324121421 is a deficient number, since it is larger than the sum of its proper divisors (1).
11324121421 is an equidigital number, since it uses as much as digits as its factorization.
11324121421 is an evil number, because the sum of its binary digits is even.
The product of its digits is 384, while the sum is 22.
Adding to 11324121421 its reverse (12412142311), we get a palindrome (23736263732).
The spelling of 11324121421 in words is "eleven billion, three hundred twenty-four million, one hundred twenty-one thousand, four hundred twenty-one".
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