11324232201103 has 2 divisors, whose sum is σ = 11324232201104. Its totient is φ = 11324232201102.

The previous prime is 11324232201097. The next prime is 11324232201151. The reversal of 11324232201103 is 30110223242311.

11324232201103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (30110223242311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11324232201103 - 2²¹ = 11324230103951 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11324232291103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662116100551 + 5662116100552.

It is an arithmetic number, because the mean of its divisors is an integer number (5662116100552).

Almost surely, 2^{11324232201103} is an apocalyptic number.

11324232201103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11324232201103 is an equidigital number, since it uses as much as digits as its factorization.

11324232201103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 11324232201103 its reverse (30110223242311), we get a palindrome (41434455443414).

The spelling of 11324232201103 in words is "eleven trillion, three hundred twenty-four billion, two hundred thirty-two million, two hundred one thousand, one hundred three".