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113244310365299 is a prime number
BaseRepresentation
bin11001101111111010111110…
…111001000110010001110011
3112211222001100200212112011022
4121233322332321012101303
5104320343321423142144
61040503415030210055
732565426402565301
oct3157727671062163
9484861320775138
10113244310365299
11330a0707a23383
121084b60a4b392b
134b25b7b1b1199
141dd70a7b4b271
15d15b274e2cee
hex66febee46473

113244310365299 has 2 divisors, whose sum is σ = 113244310365300. Its totient is φ = 113244310365298.

The previous prime is 113244310365259. The next prime is 113244310365359. The reversal of 113244310365299 is 992563013442311.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113244310365299 is a prime.

It is a super-2 number, since 2×1132443103652992 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113244310365299.

It is not a weakly prime, because it can be changed into another prime (113244310365259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56622155182649 + 56622155182650.

It is an arithmetic number, because the mean of its divisors is an integer number (56622155182650).

Almost surely, 2113244310365299 is an apocalyptic number.

113244310365299 is a deficient number, since it is larger than the sum of its proper divisors (1).

113244310365299 is an equidigital number, since it uses as much as digits as its factorization.

113244310365299 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4199040, while the sum is 53.

The spelling of 113244310365299 in words is "one hundred thirteen trillion, two hundred forty-four billion, three hundred ten million, three hundred sixty-five thousand, two hundred ninety-nine".