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113250212597 is a prime number
BaseRepresentation
bin110100101111000111…
…1010001101011110101
3101211022121020212212102
41221132033101223311
53323414023300342
6124005413031445
711116305631634
oct1513617215365
9354277225772
10113250212597
1144035879a25
1219b47325585
13a8aa999822
1456a4b1d51b
152e2c613832
hex1a5e3d1af5

113250212597 has 2 divisors, whose sum is σ = 113250212598. Its totient is φ = 113250212596.

The previous prime is 113250212591. The next prime is 113250212659. The reversal of 113250212597 is 795212052311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112546159441 + 704053156 = 335479^2 + 26534^2 .

It is a cyclic number.

It is not a de Polignac number, because 113250212597 - 216 = 113250147061 is a prime.

It is a super-2 number, since 2×1132502125972 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 113250212597.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113250212591) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56625106298 + 56625106299.

It is an arithmetic number, because the mean of its divisors is an integer number (56625106299).

Almost surely, 2113250212597 is an apocalyptic number.

It is an amenable number.

113250212597 is a deficient number, since it is larger than the sum of its proper divisors (1).

113250212597 is an equidigital number, since it uses as much as digits as its factorization.

113250212597 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37800, while the sum is 38.

The spelling of 113250212597 in words is "one hundred thirteen billion, two hundred fifty million, two hundred twelve thousand, five hundred ninety-seven".