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113252675117 is a prime number
BaseRepresentation
bin110100101111001100…
…0101010111000101101
3101211022202212222210212
41221132120222320231
53323420141100432
6124005541512205
711116335566201
oct1513630527055
9354282788725
10113252675117
114403720106a
1219b48112665
13a8ab34c63a
1456a51a0b01
152e2c94d2b2
hex1a5e62ae2d

113252675117 has 2 divisors, whose sum is σ = 113252675118. Its totient is φ = 113252675116.

The previous prime is 113252675093. The next prime is 113252675141. The reversal of 113252675117 is 711576252311.

It is a balanced prime because it is at equal distance from previous prime (113252675093) and next prime (113252675141).

It can be written as a sum of positive squares in only one way, i.e., 68693264836 + 44559410281 = 262094^2 + 211091^2 .

It is a cyclic number.

It is not a de Polignac number, because 113252675117 - 28 = 113252674861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113252675167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56626337558 + 56626337559.

It is an arithmetic number, because the mean of its divisors is an integer number (56626337559).

Almost surely, 2113252675117 is an apocalyptic number.

It is an amenable number.

113252675117 is a deficient number, since it is larger than the sum of its proper divisors (1).

113252675117 is an equidigital number, since it uses as much as digits as its factorization.

113252675117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 88200, while the sum is 41.

The spelling of 113252675117 in words is "one hundred thirteen billion, two hundred fifty-two million, six hundred seventy-five thousand, one hundred seventeen".