Base | Representation |
---|---|
bin | 110100101111001101… |
… | …1101010100011100001 |
3 | 101211022211100212201202 |
4 | 1221132123222203201 |
5 | 3323420341211233 |
6 | 124010010410545 |
7 | 11116345346066 |
oct | 1513633524341 |
9 | 354284325652 |
10 | 113253460193 |
11 | 44037697995 |
12 | 19b48430a55 |
13 | a8ab565a93 |
14 | 56a5326c6d |
15 | 2e2ca55be8 |
hex | 1a5e6ea8e1 |
113253460193 has 2 divisors, whose sum is σ = 113253460194. Its totient is φ = 113253460192.
The previous prime is 113253460163. The next prime is 113253460219. The reversal of 113253460193 is 391064352311.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 86097056929 + 27156403264 = 293423^2 + 164792^2 .
It is an emirp because it is prime and its reverse (391064352311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113253460193 - 26 = 113253460129 is a prime.
It is not a weakly prime, because it can be changed into another prime (113253460163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56626730096 + 56626730097.
It is an arithmetic number, because the mean of its divisors is an integer number (56626730097).
Almost surely, 2113253460193 is an apocalyptic number.
It is an amenable number.
113253460193 is a deficient number, since it is larger than the sum of its proper divisors (1).
113253460193 is an equidigital number, since it uses as much as digits as its factorization.
113253460193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 38.
The spelling of 113253460193 in words is "one hundred thirteen billion, two hundred fifty-three million, four hundred sixty thousand, one hundred ninety-three".
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