11325519999971 has 2 divisors, whose sum is σ = 11325519999972. Its totient is φ = 11325519999970.

The previous prime is 11325519999931. The next prime is 11325519999973. The reversal of 11325519999971 is 17999991552311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11325519999971 - 2³⁸ = 11050642093027 is a prime.

Together with 11325519999973, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11325519999895 and 11325519999904.

It is not a weakly prime, because it can be changed into another prime (11325519999973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662759999985 + 5662759999986.

It is an arithmetic number, because the mean of its divisors is an integer number (5662759999986).

Almost surely, 2^{11325519999971} is an apocalyptic number.

11325519999971 is a deficient number, since it is larger than the sum of its proper divisors (1).

11325519999971 is an equidigital number, since it uses as much as digits as its factorization.

11325519999971 is an evil number, because the sum of its binary digits is even.

The product of its digits is 62001450, while the sum is 71.

The spelling of 11325519999971 in words is "eleven trillion, three hundred twenty-five billion, five hundred nineteen million, nine hundred ninety-nine thousand, nine hundred seventy-one".