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11325519999973 is a prime number
BaseRepresentation
bin1010010011001110110110…
…0110001011001111100101
31111002201010221222000201201
42210303231212023033211
52441024131104444343
640030512210522501
72246145641423164
oct244635546131745
944081127860651
1011325519999973
113677142869983
12132ab65896431
13641cb842465a
142b222db413db
1514990950494d
hexa4ced98b3e5

11325519999973 has 2 divisors, whose sum is σ = 11325519999974. Its totient is φ = 11325519999972.

The previous prime is 11325519999971. The next prime is 11325520000031. The reversal of 11325519999973 is 37999991552311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7163662956004 + 4161857043969 = 2676502^2 + 2040063^2 .

It is a cyclic number.

It is not a de Polignac number, because 11325519999973 - 21 = 11325519999971 is a prime.

Together with 11325519999971, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11325519999896 and 11325519999905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11325519999971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662759999986 + 5662759999987.

It is an arithmetic number, because the mean of its divisors is an integer number (5662759999987).

Almost surely, 211325519999973 is an apocalyptic number.

It is an amenable number.

11325519999973 is a deficient number, since it is larger than the sum of its proper divisors (1).

11325519999973 is an equidigital number, since it uses as much as digits as its factorization.

11325519999973 is an evil number, because the sum of its binary digits is even.

The product of its digits is 186004350, while the sum is 73.

The spelling of 11325519999973 in words is "eleven trillion, three hundred twenty-five billion, five hundred nineteen million, nine hundred ninety-nine thousand, nine hundred seventy-three".