Base | Representation |
---|---|
bin | 110100101111010011… |
… | …0010100110100010111 |
3 | 101211100000121212010121 |
4 | 1221132212110310113 |
5 | 3323422100122433 |
6 | 124010150332411 |
7 | 11116411165342 |
oct | 1513646246427 |
9 | 354300555117 |
10 | 113256254743 |
11 | 44039226535 |
12 | 19b4935a107 |
13 | a8ac003a68 |
14 | 56a5853459 |
15 | 2e2ce08c2d |
hex | 1a5e994d17 |
113256254743 has 2 divisors, whose sum is σ = 113256254744. Its totient is φ = 113256254742.
The previous prime is 113256254737. The next prime is 113256254809. The reversal of 113256254743 is 347452652311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113256254743 is a prime.
It is a super-2 number, since 2×1132562547432 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 113256254743.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113256254843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56628127371 + 56628127372.
It is an arithmetic number, because the mean of its divisors is an integer number (56628127372).
Almost surely, 2113256254743 is an apocalyptic number.
113256254743 is a deficient number, since it is larger than the sum of its proper divisors (1).
113256254743 is an equidigital number, since it uses as much as digits as its factorization.
113256254743 is an evil number, because the sum of its binary digits is even.
The product of its digits is 604800, while the sum is 43.
The spelling of 113256254743 in words is "one hundred thirteen billion, two hundred fifty-six million, two hundred fifty-four thousand, seven hundred forty-three".
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