Base | Representation |
---|---|
bin | 110100101111101011… |
… | …0111101101100101111 |
3 | 101211100220121122100011 |
4 | 1221133112331230233 |
5 | 3323433331130403 |
6 | 124011323514051 |
7 | 11116624441402 |
oct | 1513726755457 |
9 | 354326548304 |
10 | 113269005103 |
11 | 44045445021 |
12 | 19b51688927 |
13 | a8b1849457 |
14 | 56a7411d39 |
15 | 2e2e0c6a6d |
hex | 1a5f5bdb2f |
113269005103 has 2 divisors, whose sum is σ = 113269005104. Its totient is φ = 113269005102.
The previous prime is 113269005097. The next prime is 113269005107. The reversal of 113269005103 is 301500962311.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (301500962311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113269005103 - 25 = 113269005071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113269005107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56634502551 + 56634502552.
It is an arithmetic number, because the mean of its divisors is an integer number (56634502552).
Almost surely, 2113269005103 is an apocalyptic number.
113269005103 is a deficient number, since it is larger than the sum of its proper divisors (1).
113269005103 is an equidigital number, since it uses as much as digits as its factorization.
113269005103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4860, while the sum is 31.
Adding to 113269005103 its reverse (301500962311), we get a palindrome (414769967414).
The spelling of 113269005103 in words is "one hundred thirteen billion, two hundred sixty-nine million, five thousand, one hundred three".
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