11330000303 has 2 divisors, whose sum is σ = 11330000304. Its totient is φ = 11330000302.

The previous prime is 11330000293. The next prime is 11330000317. The reversal of 11330000303 is 30300003311.

11330000303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an a-pointer prime, because the next prime (11330000317) can be obtained adding 11330000303 to its sum of digits (14).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11330000303 - 2⁶ = 11330000239 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11330060303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665000151 + 5665000152.

It is an arithmetic number, because the mean of its divisors is an integer number (5665000152).

Almost surely, 2^11330000303 is an apocalyptic number.

11330000303 is a deficient number, since it is larger than the sum of its proper divisors (1).

11330000303 is an equidigital number, since it uses as much as digits as its factorization.

11330000303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 14.

Adding to 11330000303 its reverse (30300003311), we get a palindrome (41630003614).

The spelling of 11330000303 in words is "eleven billion, three hundred thirty million, three hundred three", and thus it is an aban number.