Base | Representation |
---|---|
bin | 10000011111001101011… |
… | …100000111110010001111 |
3 | 11000022112022212001202021 |
4 | 100133031130013302033 |
5 | 122030412403200142 |
6 | 2224300441111011 |
7 | 144600240306106 |
oct | 20371534076217 |
9 | 4008468761667 |
10 | 1133023100047 |
11 | 3a7570002913 |
12 | 163707188467 |
13 | 82ac7582067 |
14 | 3cba520d03d |
15 | 1e714bd3267 |
hex | 107cd707c8f |
1133023100047 has 2 divisors, whose sum is σ = 1133023100048. Its totient is φ = 1133023100046.
The previous prime is 1133023099921. The next prime is 1133023100081. The reversal of 1133023100047 is 7400013203311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1133023100047 - 227 = 1132888882319 is a prime.
It is a super-2 number, since 2×11330231000472 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1133023099994 and 1133023100030.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133023100147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566511550023 + 566511550024.
It is an arithmetic number, because the mean of its divisors is an integer number (566511550024).
Almost surely, 21133023100047 is an apocalyptic number.
1133023100047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133023100047 is an equidigital number, since it uses as much as digits as its factorization.
1133023100047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 1133023100047 its reverse (7400013203311), we get a palindrome (8533036303358).
The spelling of 1133023100047 in words is "one trillion, one hundred thirty-three billion, twenty-three million, one hundred thousand, forty-seven".
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