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113310130049 is a prime number
BaseRepresentation
bin110100110000111001…
…1110101111110000001
3101211110210000000011022
41221201303311332001
53324024343130144
6124015353155225
711120634133244
oct1514163657601
9354423000138
10113310130049
1144066683886
1219b633bbb15
13a8ba21803c
1456aca7925b
152e329ebcee
hex1a61cf5f81

113310130049 has 2 divisors, whose sum is σ = 113310130050. Its totient is φ = 113310130048.

The previous prime is 113310129929. The next prime is 113310130051. The reversal of 113310130049 is 940031013311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103905009649 + 9405120400 = 322343^2 + 96980^2 .

It is a cyclic number.

It is not a de Polignac number, because 113310130049 - 216 = 113310064513 is a prime.

Together with 113310130051, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113310130949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655065024 + 56655065025.

It is an arithmetic number, because the mean of its divisors is an integer number (56655065025).

Almost surely, 2113310130049 is an apocalyptic number.

It is an amenable number.

113310130049 is a deficient number, since it is larger than the sum of its proper divisors (1).

113310130049 is an equidigital number, since it uses as much as digits as its factorization.

113310130049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 26.

The spelling of 113310130049 in words is "one hundred thirteen billion, three hundred ten million, one hundred thirty thousand, forty-nine".