Base | Representation |
---|---|
bin | 11001110000111000010010… |
… | …001011000110011111000111 |
3 | 112212012100020221002020211111 |
4 | 121300320102023012133013 |
5 | 104322433122304244421 |
6 | 1040553542302345451 |
7 | 32603246463251446 |
oct | 3160702213063707 |
9 | 485170227066744 |
10 | 113310132103111 |
11 | 331166146461a9 |
12 | 10860319b8b287 |
13 | 4b2c13aac1238 |
14 | 1dda34d888d5d |
15 | d176cadb9ee1 |
hex | 670e122c67c7 |
113310132103111 has 2 divisors, whose sum is σ = 113310132103112. Its totient is φ = 113310132103110.
The previous prime is 113310132103109. The next prime is 113310132103117. The reversal of 113310132103111 is 111301231013311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113310132103111 - 21 = 113310132103109 is a prime.
Together with 113310132103109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113310132103117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655066051555 + 56655066051556.
It is an arithmetic number, because the mean of its divisors is an integer number (56655066051556).
Almost surely, 2113310132103111 is an apocalyptic number.
113310132103111 is a deficient number, since it is larger than the sum of its proper divisors (1).
113310132103111 is an equidigital number, since it uses as much as digits as its factorization.
113310132103111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 22.
Adding to 113310132103111 its reverse (111301231013311), we get a palindrome (224611363116422).
The spelling of 113310132103111 in words is "one hundred thirteen trillion, three hundred ten billion, one hundred thirty-two million, one hundred three thousand, one hundred eleven".
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