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113310223331 is a prime number
BaseRepresentation
bin110100110000111010…
…0001100101111100011
3101211110210011202010012
41221201310030233203
53324024404121311
6124015355155135
711120635002224
oct1514164145743
9354423152105
10113310223331
1144066737978
1219b63445aab
13a8ba24b636
1456acaa124b
152e32a1978b
hex1a61d0cbe3

113310223331 has 2 divisors, whose sum is σ = 113310223332. Its totient is φ = 113310223330.

The previous prime is 113310223319. The next prime is 113310223333. The reversal of 113310223331 is 133322013311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113310223331 - 218 = 113309961187 is a prime.

It is a super-2 number, since 2×1133102233312 (a number of 23 digits) contains 22 as substring.

Together with 113310223333, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113310223297 and 113310223306.

It is not a weakly prime, because it can be changed into another prime (113310223333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655111665 + 56655111666.

It is an arithmetic number, because the mean of its divisors is an integer number (56655111666).

Almost surely, 2113310223331 is an apocalyptic number.

113310223331 is a deficient number, since it is larger than the sum of its proper divisors (1).

113310223331 is an equidigital number, since it uses as much as digits as its factorization.

113310223331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 113310223331 its reverse (133322013311), we get a palindrome (246632236642).

The spelling of 113310223331 in words is "one hundred thirteen billion, three hundred ten million, two hundred twenty-three thousand, three hundred thirty-one".