Base | Representation |
---|---|
bin | 1010010011100011101101… |
… | …1101000100000011001101 |
3 | 1111010020121022121112112211 |
4 | 2210320323131010003031 |
5 | 2441122114011420412 |
6 | 40033240100030421 |
7 | 2246434514022316 |
oct | 244707335040315 |
9 | 44106538545484 |
10 | 11331121201357 |
11 | 3679557575431 |
12 | 1330069692411 |
13 | 64269b9ac8b9 |
14 | 2b26019bd60d |
15 | 149b36114ca7 |
hex | a4e3b7440cd |
11331121201357 has 2 divisors, whose sum is σ = 11331121201358. Its totient is φ = 11331121201356.
The previous prime is 11331121201327. The next prime is 11331121201373. The reversal of 11331121201357 is 75310212113311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9478307486596 + 1852813714761 = 3078686^2 + 1361181^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331121201357 - 211 = 11331121199309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331121201327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665560600678 + 5665560600679.
It is an arithmetic number, because the mean of its divisors is an integer number (5665560600679).
Almost surely, 211331121201357 is an apocalyptic number.
It is an amenable number.
11331121201357 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331121201357 is an equidigital number, since it uses as much as digits as its factorization.
11331121201357 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3780, while the sum is 31.
Adding to 11331121201357 its reverse (75310212113311), we get a palindrome (86641333314668).
The spelling of 11331121201357 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, two hundred one thousand, three hundred fifty-seven".
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