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11331121201357 is a prime number
BaseRepresentation
bin1010010011100011101101…
…1101000100000011001101
31111010020121022121112112211
42210320323131010003031
52441122114011420412
640033240100030421
72246434514022316
oct244707335040315
944106538545484
1011331121201357
113679557575431
121330069692411
1364269b9ac8b9
142b26019bd60d
15149b36114ca7
hexa4e3b7440cd

11331121201357 has 2 divisors, whose sum is σ = 11331121201358. Its totient is φ = 11331121201356.

The previous prime is 11331121201327. The next prime is 11331121201373. The reversal of 11331121201357 is 75310212113311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9478307486596 + 1852813714761 = 3078686^2 + 1361181^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331121201357 - 211 = 11331121199309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331121201327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665560600678 + 5665560600679.

It is an arithmetic number, because the mean of its divisors is an integer number (5665560600679).

Almost surely, 211331121201357 is an apocalyptic number.

It is an amenable number.

11331121201357 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331121201357 is an equidigital number, since it uses as much as digits as its factorization.

11331121201357 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780, while the sum is 31.

Adding to 11331121201357 its reverse (75310212113311), we get a palindrome (86641333314668).

The spelling of 11331121201357 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, two hundred one thousand, three hundred fifty-seven".