Base | Representation |
---|---|
bin | 1010010011100011101110… |
… | …0000011111011011101111 |
3 | 1111010020121101022012012002 |
4 | 2210320323200133123233 |
5 | 2441122114224144301 |
6 | 40033240131202515 |
7 | 2246434524454163 |
oct | 244707340373357 |
9 | 44106541265162 |
10 | 11331122099951 |
11 | 3679558029575 |
12 | 1330069a4643b |
13 | 64269bc35904 |
14 | 2b2601b74ca3 |
15 | 149b3624116b |
hex | a4e3b81f6ef |
11331122099951 has 2 divisors, whose sum is σ = 11331122099952. Its totient is φ = 11331122099950.
The previous prime is 11331122099933. The next prime is 11331122099993. The reversal of 11331122099951 is 15999022113311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331122099951 - 210 = 11331122098927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11331122099896 and 11331122099905.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331122099051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561049975 + 5665561049976.
It is an arithmetic number, because the mean of its divisors is an integer number (5665561049976).
Almost surely, 211331122099951 is an apocalyptic number.
11331122099951 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331122099951 is an equidigital number, since it uses as much as digits as its factorization.
11331122099951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 131220, while the sum is 47.
The spelling of 11331122099951 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, ninety-nine thousand, nine hundred fifty-one".
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