11331131320037 has 2 divisors, whose sum is σ = 11331131320038. Its totient is φ = 11331131320036.

The previous prime is 11331131320031. The next prime is 11331131320139. The reversal of 11331131320037 is 73002313113311.

It is a happy number.

11331131320037 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8056366963876 + 3274764356161 = 2838374^2 + 1809631^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331131320037 - 2¹⁶ = 11331131254501 is a prime.

It is a super-2 number, since 2×11331131320037² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331131319991 and 11331131320009.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331131320031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565660018 + 5665565660019.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565660019).

Almost surely, 2^{11331131320037} is an apocalyptic number.

It is an amenable number.

11331131320037 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131320037 is an equidigital number, since it uses as much as digits as its factorization.

11331131320037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402, while the sum is 29.

Adding to 11331131320037 its reverse (73002313113311), we get a palindrome (84333444433348).

The spelling of 11331131320037 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred twenty thousand, thirty-seven".